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Im am using response = FTP.SendCommand("CHMOD 0" & CHMOD.Label3.Caption & " " & ListViewRemote.ListItems(x1).Text)

What is wrong? CHMOD not understood?? Why?

Log: FtpCmdSent= MLSD FtpCmdResp= 150 Opening BINARY mode data connection for MLSD FtpCmdResp= 226 Transfer complete FtpCmdSent= PWD FtpCmdResp= 257 "/Test/wring333" is the current directory FtpCmdSent= CHMOD 0744 book01b.ico FtpCmdResp= 500 CHMOD not understood ChilkatLog: SendCommand: DllDate: May 8 2015 ChilkatVersion: UnlockPrefix: Anything for 30-day trial Username: LÜTGENSWIN8:Christian Ltgens Architecture: Little Endian; 32-bit Language: ActiveX VerboseLogging: 0 command: CHMOD 0744 book01b.ico sendCommand: sendingCommand: CHMOD 0744 book01b.ico --sendCommand readCommandResponse: replyLineQP: 500 CHMOD not understood --readCommandResponse statusCode: 500 Failed. --SendCommand --ChilkatLog

asked Jun 01 '15 at 06:46

Christian's gravatar image


The right shall command works like this: FTP.SendCommand ("SITE CHMOD" If the help is not correct?

Now I would have to know how to read Permissons. Has an idea?



answered Jun 01 '15 at 07:18

Christian's gravatar image


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Asked: Jun 01 '15 at 06:46

Seen: 643 times

Last updated: Jun 01 '15 at 07:18

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